(2x/(x^2-36))-(1/(x-6))

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Solution for (2x/(x^2-36))-(1/(x-6)) equation: 


D( x )

x-6 = 0

x^2-36 = 0

x-6 = 0

x-6 = 0

x-6 = 0 // + 6

x = 6

x^2-36 = 0

x^2-36 = 0

1*x^2 = 36 // : 1

x^2 = 36

x^2 = 36 // ^ 1/2

abs(x) = 6

x = 6 or x = -6

x in (-oo:-6) U (-6:6) U (6:+oo)

(2*x)/(x^2-36)-(1/(x-6)) = 0

(2*x)/(x^2-36)-(x-6)^-1 = 0

(2*x)/(x^2-36)-1/(x-6) = 0

(2*x*(x-6))/((x^2-36)*(x-6))+(-1*(x^2-36))/((x^2-36)*(x-6)) = 0

2*x*(x-6)-1*(x^2-36) = 0

x^2-12*x+36 = 0

x^2-12*x+36 = 0

x^2-12*x+36 = 0

DELTA = (-12)^2-(1*4*36)

DELTA = 0

x = 12/(1*2)

x = 6 or x = 6

(x-6)^2 = 0

((x-6)^2)/((x^2-36)*(x-6)) = 0

((x-6)^2)/((x^2-36)*(x-6)) = 0 // * (x^2-36)*(x-6)

(x-6)^2 = 0

x-6 = 0 // + 6

x = 6

x in { 6} 

x belongs to the empty set

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